Note Down The below questions.
So The Trick is very Small.
Let's solve the 1st question.
Algorithm:
1.Take the unit digit of the number and place as the unitdigit of answer.
2.Add The Digits in ascending manner then descending from the right.
i.e; 1st add 2 digit then 3 digit then 4 digits.
(AS PER NO. OF 1'S)
so here two 1 is available.
3. Add 3+2=5
(If the addition become greater than 10 the pick the 1 to the left digit.)
4.make the Answer 352.
So let's move to the Second question.
Algorithm:
Do as per the above trick.
1.place 2 as the right digit.
2. Add 1st 2 digit i.e; 5+2=7
3. Then add another 2 digit 5+6=11
4 combine them to get answer
____2
___7
11
6
____________
7172
let's move to the third question.
Algorithm:
1.place 3 as right digit
2. Here no. Of 1 is 3.so we do 3 digit addition maximally.But starts from 2 digit addition.
3.add 0+3=3
4.add 2+0+3=5
5.add 2+0=2
6. Place the 2 as left digit.
So answer is 22533.
I REPEAT IF YOU HAVE ANY DOUBT PLEASE COMMENT ME.
Lets Take another Example.
201432×111
Algorithm:
The (2) in the units place of the multiplicand is written as the units digit of the answer
• We move to the left and add (2 + 3) and write 5
• We move to the left and add (2 + 3 + 4) and write 9
• We move to the left and add (3 + 4 + 1) and write 8
• We move to the left and add (4 + 1 + 0) and write 5
• We move to the left and add (1 + 0 + 2) and write 3
• We move to the left and add (0 + 2) and write 2
• We move to the left and write the single digit (2) in the answer.
Ex.210432×1111
AND the last two questions are H.W. For You.